multiple Algorithm

The multiple of 3 algorithm is a simple and effective method to determine if a given number is a multiple of 3. This algorithm is based on the property of the divisibility rule for 3, which states that a number is divisible by 3 if the sum of its digits is also divisible by 3. The algorithm works by adding up the digits of the number and checking if the resulting sum is divisible by 3. If the sum is divisible by 3, then the original number is also a multiple of 3. Otherwise, the number is not a multiple of 3. This method can be easily implemented in various programming languages and can be used to test numbers of any size. To use the multiple of 3 algorithm, first, break down the given number into individual digits. Then, sum up the digits and check if the sum is divisible by 3. If necessary, repeat the process for the sum until a single-digit number is obtained. If the final single-digit sum is 3, 6, or 9, then the original number is a multiple of 3. This algorithm is not only applicable to base 10 numbers but also works for numbers in other bases. In essence, the multiple of 3 algorithm provides a quick and efficient way to verify the divisibility of numbers by 3, making it a valuable tool in various mathematical and programming applications.
function ans = multiple(x, m)

  % multiple : checks whether the first number is 
  % divisible through the second number.
  % INPUTS: The inputs must be integers.
  % OUTPUT: Is a boolean value 0 or 1.
  % THROWS: Throws a assertion error if the inputs invalid.

  assert((isnumeric(x) && isnumeric(m)), "The inputs must be integers")

  if m == 0 
    ans = (x == 0);
  else
    ans = (mod(x,m) == 0);
  end

endfunction

LANGUAGE:

DARK MODE: